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Bet The Flip (β)
Your current points are 10.
Current win streak: 2
Win streak bonus: x1.5
Which one will you bet on?
How much would you like to bet?
You're betting 3 points on heads.
If you're ready, please tap the button below, and flip your coin!
Result
You Win! You've earned points!
Current points: 10
Work out any coin flip probability instantly: the chance of exactly, at least, or at most k heads in n flips, and the odds of a streak of heads somewhere in a run. Answers come as a percent, odds (“1 in …”), and an exact fraction for small runs — with the binomial formula explained below.
Set the per-flip chance to 0.5 for a fair coin, or change it to model a biased coin. Exact fractions are shown for runs of 30 flips or fewer with a fair coin.
Computes the chance that at least one unbroken run of length s (or longer) appears anywhere in n fair flips. Long streaks are a normal feature of randomness — not proof of a rigged coin.
| Question | Probability |
|---|---|
| Heads on a single flip | 1/2 = 50% |
| Two heads in a row (2 flips) | 1/4 = 25% |
| Exactly 2 heads in 3 flips | 3/8 = 37.5% |
| At least 2 heads in 3 flips | 1/2 = 50% |
| Exactly 5 heads in 10 flips | 252/1024 ≈ 24.6% |
| All heads in 5 flips | 1/32 ≈ 3.1% |
| Ten heads in a row (10 flips) | 1/1024 ≈ 0.098% |
| A run of 2+ heads somewhere in 10 flips | 880/1024 ≈ 85.9% |
| Exactly 50 heads in 100 flips | ≈ 8.0% |
The probability of getting exactly k heads in n independent flips follows the binomial distribution:
P(X = k) = C(n, k) × pk × (1 − p)n−k
C(n, k) counts how many orderings put the k heads among the n flips, and p is the chance of heads on one flip (0.5 for a fair coin). Worked example — exactly 2 heads in 3 flips: C(3, 2) = 3 orderings (HHT, HTH, THH), each with probability (1/2)³ = 1/8, so P = 3/8 = 37.5%. For “at least” or “at most” questions, add up the matching terms — that is exactly what the calculator above does.